The sum of the digits of a two-digit number is 9. If 27 is added to it, the digits are reversed. Find the number.
36
Let the digit in the ten's place be x and digit in the unit's place be y
Sum of the digit is 9 ;therefore we have
x+y=9----------------(1)
The number = 10x+y ; when digits are reversed, the number becomes 10y+x ;
∴ we have,
10x+y+27=10y+x⇒9x−9y=−27
⇒x−y=−3__________(2)
Adding (2) and (1) we get,
2x=6⇒x=3 and y=6.
Therefore the number formed is 36.