The sum of the digits of a two digit number is 9. When 9 is added to the number, the digits of the number will reverse.
What is the original number?
45
Since sum of the digits is 9, if one digit is x then the other digit will be 9 – x.
Let the digit in the ten’s place be x and units place be (9 – x).
The number is 10x + (9 – x). After reversing the digits , the number will be 10(9 – x) + x.
10x + (9 – x) + 9 = 10(9-x) + x (given)
9x + 18 = 90 -9x
9x + 9x = 90 – 18
18 x = 72
x = 72 ÷ 18 = 4
∴ The number is 45.