Question

The sum of the digits of two number is 11 if the digits are reversed the number decreases by 45 The original number is

• A. 38
• B. 65
• C. 74
• D. 83

Answer 1

The correct option is A 38

Let t is 10's digit and u is unit digit
$t+u=11$
$10u+t=45+(10t+u)$
Combine like terms: $9u-9t=45$
Solve by elimination:
$9u-9t=45$
$-9u-9t=-99$
$-18t=-54$
$t=3,u=8$
$Originalnumberis38$