The sum of the distances of a point P from two perpendicular lines in plane is 1 Then locus of p is
We have,
Let the x and y axes be perpendicular lines.
According to given question
Sum of the distance would be x+y=1
So, in the first quadrant, the locus of points would look like a straight line with points (0,1) and (1,0).
In the second quadrant, the locus of points would look like a straight line with points (0,1) and (−1,0).
In the Third quadrant, the locus of points would look like a straight line with points (0,−1) and (1,0).
When you put it all together, it would be a square 45o degree about the origin.
The length of the side of the square would be √2.