The sum of the first 10 terms of the series 5 + 8 + 11 + … is:

185

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180

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190

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195

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Solution

The correct option is A 185
Sum of first nth term $= S_{n} = \frac{n}{2} (2 a + (n - 1) d)$ .

Given,
$1^{s t}$ term (a)= 5
$2^{n d}$ term = 8

common difference (d) = 2nd term - 1st term = 8 - 5 = 3

Sum of first 10 terms $S_{10} = \frac{n}{2} (2 a + (n - 1) d) = \frac{10}{2} (2 \times 5 + (10 - 1) 3) = 185$

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