The sum of the first 1000 positive integers is nbsp- -50051-500500-50050-5005-

The correct option is B 500500 The first 1000 positive integers are 1,2,3,4....., 1000. ⇒ n =1000 The sum of first n natural numbers is given by S_n =n(n+1)/2. ...

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Standard X

Mathematics

Sum of Terms of 1st 'n' Natural Numbers

The sum of th...

Question

The sum of the first 1000 positive integers is ___.

50051

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500500

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50050

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5005

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Solution

The correct option is B
500500

The first 1000 positive integers are 1,2,3,4....., 1000.

$\Rightarrow n = 1000$

The sum of first $n$ natural numbers is given by
$S_{n} = \frac{n (n + 1)}{2} .$

$\Rightarrow S_{1000} = \frac{1000 \times 1001}{2}$

$= 500 \times 1001$

$= 500500$

Suggest Corrections

The sum of the first 1000 positive integers is ___.

The correct option is B 500500 The first 1000 positive integers are 1,2,3,4....., 1000. ⇒n=1000 The sum of first n natural numbers is given by Sn=n(n+1)2. ⇒S1000=1000×10012 =500×1001 =500500

The correct option is B
500500

The first 1000 positive integers are 1,2,3,4....., 1000.

$\Rightarrow n = 1000$

The sum of first $n$ natural numbers is given by
$S_{n} = \frac{n (n + 1)}{2} .$

$\Rightarrow S_{1000} = \frac{1000 \times 1001}{2}$

$= 500 \times 1001$

$= 500500$