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Question

The sum of the first 20 terms of the series 12+2232+4252+62..... is

A
210
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B
519
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C
190
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D
420
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E
820
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Solution

The correct option is E 820
We have
1222+3242+5262..................
=(1+2)(12)+(3+4)(34)+(5+6)(56).......
=3+(7)+(11)+...........
The list an A.P with d=4 and a=3
So S20=202[2(3)+(201)(4)]=820

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