The sum of the first 25 terms of an arithmetic sequence is 1,400, and the 25th term is 104. Find the value of a2−a1 where the first term of the sequence is a1 and the second term is a2.
A
−3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
4
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
5
No worries! We‘ve got your back. Try BYJU‘S free classes today!
E
8
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is C4 The difference between first term and second term is common difference. Let the common difference be d and first term be a. ⇒a+24d=104 , 25a+25×12d=1400 ⇒a+12d=56 and a+24d=104 ⇒12d=48