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Question

The sum of the first 25 terms of an arithmetic sequence is 1,400, and the 25th term is 104. Find the value of a2−a1 where the first term of the sequence is a1 and the second term is a2.

A
3
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B
2
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C
4
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D
5
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E
8
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Solution

The correct option is C 4
The difference between first term and second term is common difference.
Let the common difference be d and first term be a.
a+24d=104 , 25a+25×12d=1400
a+12d=56 and a+24d=104
12d=48
d=4

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