Question

The sum of the first 7 terms of an A.P. is 63 and the sum of its next 7 terms is 161. Find the 28^th term of this A.P.

Answer 1

Let a be the first term and d be the common difference.

We know that, sum of first n terms = S_n = $\frac{n}{2}$[2a + (n − 1)d]

It is given that sum of the first 7 terms of an A.P. is 63.
And sum of next 7 terms is 161.
∴ Sum of first 14 terms = Sum of first 7 terms + sum of next 7 terms
= 63 + 161 = 224

Now,
S₇ = $\frac{7}{2}$[2a + (7 − 1)d]
⇒ 63 = $\frac{7}{2}$(2a + 6d)
⇒ 18 = 2a + 6d
⇒ 2a + 6d = 18 ....(1)

Also,
S₁₄ = $\frac{14}{2}$[2a + (14 − 1)d]
⇒ 224 = 7(2a + 13d)
⇒ 32 = 2a + 13d
⇒ 2a + 13d = 32 ....(2)

On subtracting (1) from (2), we get
13d − 6d = 32 − 18
⇒ 7d = 14
⇒ d = 2
⇒ 2a = 18 − 6d [From (1)]
⇒ 2a = 18 − 6 × 2
⇒ 2a = 18 − 12
⇒ 2a = 6
⇒ a = 3

Also, n^th term = a_n = a + (n − 1)d
⇒ a₂₈ = 3 + (28 − 1)2
= 3 + 27 × 2
= 57

Thus, 28^th term of this A.P. is 57.