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Byju's Answer

Standard VIII

Mathematics

Finding Square Root of a Number

The sum of th...

Question

The sum of the first N natural numbers is equal to $x^{2}$ where x is an integer less than 100. What are the values that N can take?

1, 9, 27

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1, 7, 26

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1, 8, 48

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1, 8, 49

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Solution

The correct option is C $1, 8, 49$
sum of first $N$ natural numbers is $= \frac{n (n + 1)}{2}$

$\frac{n (n + 1)}{2} = x^{2}$
$x < 100$ (integer)

for $N = 1, 8, 49$ sum will be $x^{2}$ for $x = 1, 6, 35$

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The sum of the first N natural numbers is equal to x2 where x is an integer less than 100. What are the values that N can take?

The correct option is C 1,8,49sum of first N natural numbers is =n(n+1)2n(n+1)2=x2x<100 (integer)for N=1,8,49 sum will be x2 for x=1,6,35

The sum of the first N natural numbers is equal to $x^{2}$ where x is an integer less than 100. What are the values that N can take?

The correct option is C $1, 8, 49$
sum of first $N$ natural numbers is $= \frac{n (n + 1)}{2}$

$\frac{n (n + 1)}{2} = x^{2}$
$x < 100$ (integer)

for $N = 1, 8, 49$ sum will be $x^{2}$ for $x = 1, 6, 35$