Sum of n terms, Sn=5n22+3n2
S1=5(1)22+3(1)2=52+32=82=4=a
S1=5(2)22+3(2)2=202+62=10+3=13
a2=S2−S1=13−4=9
d=a2−a1=9−4=5
an=a+(n−1)d=4+(n−1)5=4+5n−5=5n−1
a20=5n−1=5×20−1=100−1=99
(i) the sum fo the first n terms of an AP is (5n22+3n2). Find hte nth term and the 20th term of this AP. (ii) The sum of the first n terms of an AP is (3n22+5n2). Find its nth term and the 25th term.