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Question

The sum of the integers from 1 to 100 which are divisible by 3 and 5, is :

A
2317
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B
2632
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C
315
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D
2489
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Solution

The correct option is C 315
Integers divisible by 3 are {3,6,9,12,15,.....99}
Integers divisible by 5 are {5,10,15,25,30,.....95,100}
Set of integers which are divisible by both 3 and 5 is the intersection of above sets and that is
{15,30,45,....,90} i.e. multiples of 15 upto 100
Sum of the integers which are divisible both 3 and 5
=15+30+45+...+90
=62(15+90)..(as there are six such numbers)
=315

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