Question

The sum of the intercepts cut off by the plane $2x+y-2z=5$ on the coordinate axes is

Answer 1

Given plane :
$2x+y-2z=5$
converting into intercept form :
$\Rightarrow \frac{x}{5/2}+\frac{y}{5}+\frac{z}{-5/2}=1$
So, intercepts are : $\frac{5}{2},5,-\frac{5}{2}$
$\therefore$ sum of intercept $=5$