Question

The sum of the interior angles of a pentagon is...................

Answer 1

We know that, the sum of interior angles of an n-sided polygon is $(n-2)\times {180}^{\circ }$

For a pentagon, $n=5$

$\therefore$ Sum of the interior angles $=(5-2)\times {180}^{\circ }$

$={540}^{\circ }$

Hence, the sum of the interior angles of a pentagon is ${540}^{\circ }$.