The sum of the largest and the smallest angle of the given triangle is:

∠ B + ∠ C

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∠ B + ∠ A

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∠ A + ∠ C

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Cannot be determined

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Solution

The correct option is B $∠ B + ∠ A$
Given, in $Δ A B C$ , BC = 4 cm, AB = 6 cm and AC = 7 cm.
Hence, the ascending order of sides is BC, AB, AC.
In any triangle, the angle opposite to longer side is larger.
$∴$ Ascending order of angles is $∠ A, ∠ C, ∠ B$ .
$\Rightarrow ∠ A < ∠ C < ∠ B$
$∴$ The sum of the largest and the smallest angle of the given triangle is given by $∠ B + ∠ A$ .

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