Question

The sum of the length, breadth and height of cuboid is $38$ cm and the length of its diagonal is $22$ cm. Find the surface area of the cuboid.

• A. Given : $1+b+h=38$ and $l^2+b^2+h^2={22}^2$
  To find : $2(lb+bh+hl)$
  ans $960$ sq.cm
• B. Given : $1+b+h=38$ and $l^2+b^2+h^2={22}^2$
  To find : $2(lb+bh+hl)$
  ans $900$ sq.cm
• C. Given : $1+b+h=38$ and $l^2+b^2+h^2={22}^2$
  To find : $2(lb+bh+hl)$
  ans $930$ sq.cm
• D. Given : $1+b+h=38$ and $l^2+b^2+h^2={22}^2$
  To find : $2(lb+bh+hl)$
  ans $660$ sq.cm

Answer 1

The correct option is A Given : $1+b+h=38$ and $l^2+b^2+h^2={22}^2$

To find : $2(lb+bh+hl)$
ans $960$ sq.cm
$l+b+h=38,l^2+b^2+h^2={22}^2$
$(l+b+h{)}^2=l^2+b^2+c^2+2lb+2bh+2lh$
${38}^2={22}^2+2(lb+bh+lh)$
$1444=484+2(lb+bh+lh)$
$2(lb+bh+lh)=960Sq.cm=Surfaceareaofthecubiod$