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Question

The sum of the length of tangent and subtangent at a point of y=alog(x2a2)(a>0) is proportional to?

A
|x|
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B
|y|
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C
|xy|
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D
xy
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Solution

The correct option is A |xy|
Length of the tangent = |y| 1+(dxdy)2
Length of the sub-tangent = ydxdy
dydx=2axx2a2
Length of the tangent = |y|x2+a22ax
Length of the sub-tangent = |y|x2a22ax
Sum = |xy|a|xy|

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