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Question

The sum of the number of lone pairs of electrons on each central atom in the following species is:

[TeBr6]2, [BrF2]+, SNF3, and [XeF3].

[Atomic numbers: N=7, F=9, S=16, Br=35, Te=52, Xe=54]

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Solution

The sum of the number of lone pairs of electrons on each central atom in the given species is 1+2+0+3=6.
Te atom in [TeBr6]2 has 1 lone pair of electrons.
Br atom in [BrF2]+ has 2 lone pairs of electrons.
S atom in SNF3 has 0 lone pair of electrons.
Xe atom in [XeF3] has 3 lone pairs of electrons.

682625_640528_ans_0164f512a66c4b52b73e9bbe5fc8b6a6.png

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