The sum of the radius and the height of a solid cylinder is 37 cm If the total surface area of the solid is $1628 c m^{2}$ find the circumference of the base

30 cm

No worries! We‘ve got your back. Try BYJU‘S free classes today!

34 cm

No worries! We‘ve got your back. Try BYJU‘S free classes today!

44 cm

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

40 cm

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C 44 cm
r+h=37 cm
Total surface area=1628 $c m^{2}$
Also Total surface area= $2 π r (r + h)$
$∴ 1628 = 2 π r (37)$
or $2 π r = \frac{1628}{37} = 44$
$∴$ Circumference=44 cm
'

Suggest Corrections

Similar questions

Q. The sum of the radius of the base and height of a solid cylinder is

37

c m .

If the total surface area is

1628 {c m}^{2},

find the volume of the cylinder.

The sum of the radius of base and height of a solid right circular cylinder is 37 cm. If the total surface area of the solid cylinder is 1628 $c m^{2}$ , find the volume of cylinder.

Q. The sum of height and radius of the base of a solid cylinder is

37 c m

. Total surface area f the cylinder is

1628 c m^{2}

, Find its volume of the cylinder.

Join BYJU'S Learning Program

The sum of the radius and the height of a solid cylinder is 37 cm If the total surface area of the solid is 1628cm2 find the circumference of the base

The correct option is C 44 cmr+h=37 cmTotal surface area=1628 cm2Also Total surface area= 2πr(r+h)∴1628=2πr(37)or 2πr=162837=44∴ Circumference=44 cm'

The sum of the radius and the height of a solid cylinder is 37 cm If the total surface area of the solid is $1628 c m^{2}$ find the circumference of the base

The correct option is C 44 cm
r+h=37 cm
Total surface area=1628 $c m^{2}$
Also Total surface area= $2 π r (r + h)$
$∴ 1628 = 2 π r (37)$
or $2 π r = \frac{1628}{37} = 44$
$∴$ Circumference=44 cm
'