The sum of the rational terms in the expansion of (√2+5√3)10 is:
41
42
39
45
Tr+1 = 10Cr10−r22.3r5
This is rational, if 10−r2 and r5 are integers.
∴ There are only two rational terms.
Namely 10C0(√2)10(315)0and 10C10(√2)0(315)10
∴ sum = 32 + 9 = 41
The sum of the rational terms in the expansion of (√2+31/5)10 is