The correct option is A 1
52x2−2.5x2+x+1−3.52x+3=0
Dividing the expression by 52x,
52x2−2x−10.5x2−x−3.53=0
Let, 5x2−x=t
On substitution,
t2−10t−375=0
(t−25)(t+15)=0⇒t=25,−15
But, t>0, hence we reject t=−15
∴5(x2−x)=52⇒x2−x=2
x2−x−2=0⇒(x−2)(x+1)=0
x=2,−1
∴ Sum of the real roots is =1.