The sum of the series 1 + 2x + 3 x2 + 4 x3 + ..........upto n
terms is
Let Sn be the sum of the given series to n terms, then
Sn = 1 + 2x + 3 x2 + 4 x3 + ....... + n xn−1 ..........(i)
xSn = x + 2 x2 + 3 x2 + ...........+ n xn ..........(ii)
Subtracting (ii) from (i), we get
(1-x)Sn = 1 + x + x2 + x3 + ......... to n terms -n xn
= ( (1−xn)(1−x)) - nxn
⇒ Sn = (1−xn)−nxn(1−x)(1−x)2 = 1−(n+1)xn+nxn+1(1−x)2