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B
219
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C
219+12.20C10
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D
219−12.20C10
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Solution
The correct option is C219+12.20C10 (1+x)20=20C0+20C1x+........+20C20x20 220=20C0+20C1+....+20C10+20C11+........+20C20 219=20C0+.....+20C9+20C10−1220C10 ∴20C0+→+20C10=219+1220C10