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Question

The sum of the series 20C0−20C1−20C2−20C3........20C10is

A
0
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B
(12)20C10
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C
20C10
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D
(13)20C10
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Solution

The correct option is B (12)20C10
20C020C1+20C220C3+......+20C10

we know that

(1+x)20=20C0+20C1x+......+20C10x10+.....+20C20x2a

Put x=1 in the above expansion

0=20C020C1+20C2+.......20C9+20C1020C11+....+20C20

0=20C020C1+20C2+......+20C9+20C102C9+2C8......+20C0

0=2(20C020C1+......20C9)+20C10

2(20C020C1+......+20C10)+20C10+20C10=20C10

2(20C020C1+......+20C10)=20C10

20C020C1+.....+20C10=1220C10

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