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Question

The sum of the series 2020C02020C1+2020C22020C3+.....+2020C1010 is

A
122020C1010
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B
2020C1010
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C
Zero
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D
122020C1010
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Solution

The correct option is A 122020C1010

(1x)m=nC0nC1x++nCnxn
Put x=1 and n=2020
0=2020C02020C1+2020C2+2020C2020
also nCr=nCnr
2020C2020=2020Co
[2[2020C02020C1+]+2020C1010]=0
So 2020C02020C1+2020C1009=
122020C1010



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