The sum of the series
$3, 6, 9, . . . . ., 45$

360

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

513

No worries! We‘ve got your back. Try BYJU‘S free classes today!

135

No worries! We‘ve got your back. Try BYJU‘S free classes today!

531

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is D 360
Given series is $3, 6, 9, . . . . ., 45$
Common difference is $6 - 3 = 3$
No of terms is $a_{n} = a + (n - 1) d 45 = 3 + (n - 1) 3 42 = (n - 1) 3 n - 1 = 14 n = 15$
Sum of terms is $\frac{15}{2} [2 (3) + (15 - 1) 3] \frac{15}{2} [6 + 42] 15 \times 24 = 360$

Suggest Corrections

Similar questions

11 + 23 + 45 + 87 . . .

n

30

1 - 50 + 4 - 45 + 7 - 40 +

15

45

\frac{1}{9} + \frac{1}{18} + \frac{1}{30} + \frac{1}{45} + \frac{1}{63} + . . . .

(45^{2} - 43^{2}) + (44^{2} - 42^{2}) + (43^{2} - 41^{2}) + \dots

Join BYJU'S Learning Program