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Question

The sum of the series 11.212.3+13.4.. is

A
loge2
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B
2loge2
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C
loge21
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D
loge4e
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Solution

The correct option is A loge4e
Let given series: s=11.212.3+13.4...

let: s1=11.2+13.4+15.6+...

tn=1(2n1)(2n)

tn=12n112n

sn=tn

sn=(12n112n)

tn=112+1314+15...

tn=loge2......Eq:01

Solve: s2=12.3+14.5+16.7+...

sn=tn

sn=(12n12n+1)

tn=1(2n)(2n+1)

tn=12n12n+1

tn=(1213)+(1314)+...

tn=1loge2......Eq:02

tn=(12+1314+...)

tn=(loge21)

tn=1loge2......Eq:02

Required summation of series (s)= Eq:01-Eq:02;

s=tntn

s=loge21+loge2

s=2loge2

s=loge22

s=loge4

s=log4e

Option (D) is correct.


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