The sum of the series 131+13+231+3+13+23+331+3+5+…… upto 16 terms is
A
246
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
646
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
446
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
746
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is C446 Given : 131+13+231+3+13+23+331+3+5+……
Now, Tn=n∑r=1r3n∑r=1(2r−1)⇒Tn=14×n2(n+1)22(n(n+1)2)−n⇒Tn=14(n+1)2⇒S16=14(22+32+42+⋯172)⇒S16=14(12+22+32+42+⋯172−12)⇒S16=14(17(17+1)(2⋅17+1)6−1)∴S16=446