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Question

The sum of the series 21!+62!+123!+204!+... is


A
3e2
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B
e
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C
2e
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D
3e
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Solution

The correct option is D 3e
Writing the general term, we get
Tn=n(n+1)n!
=n+1(n1)!
Reconstructing the series, we get
S=2+3+42!+53!...
=d(x2ex)dxx=1
=[2xex+x2ex]x=1
=2e+e
=3e

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