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B
e
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C
2e
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D
3e
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Solution
The correct option is D3e Writing the general term, we get Tn=n(n+1)n! =n+1(n−1)! Reconstructing the series, we get S=2+3+42!+53!...∞ =d(x2ex)dxx=1 =[2xex+x2ex]x=1 =2e+e =3e