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Question

The sum of the series 1+22+322+423+524++100299, is

A
992100
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B
992100+1
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C
1002100
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D
none of these
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Solution

The correct option is B 992100+1
Let S=1+22+322+423+524+100299 .................. (1)
Multiply (1) by 2
2S=2+222+323+1002100............(2)
Subtracting (1) and (2) gives
(12)S=1+2+22+23+2991002100
S=2100121100.2100S=199.2100
S=1+992100

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