The sum of the series 1(√2+√1)+1(√2+√3)+......+1(√120+√121) is:
A
10
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B
11
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C
12
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D
None of these
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Solution
The correct option is A 10 The first term sum of the series is √2−1, for 2 terms we have the sum as √3−1 and so on. For the given series of 120 terms the sum would be √121−1=10.