The sum of the squares of $2$ numbers is $156$ . If the one number is $5$ , the square of the other number is

81

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131

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11

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123

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Solution

The correct option is B $131$
Let the two numbers be $x$ and $y$ .
$x^{2}$ $+$ $y^{2}$ $\to$ $156$
$x$ $\to$ 5
$x$ $\to$ $5 \times 5$ $\to$ $25$
Substituting, $25$ $+$ $y^{2}$ $\to$ $156$
$y^{2}$ $\to$ $156 - 25$ $\to$ $131$

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The sum of the squares of 2 numbers is 156. If the one number is 5, the square of the other number is

The correct option is B 131Let the two numbers be x and y.x2 + y2 → 156x → 5x → 5×5 → 25Substituting, 25 + y2 → 156y2 → 156−25 → 131

The sum of the squares of $2$ numbers is $156$ . If the one number is $5$ , the square of the other number is

The correct option is B $131$
Let the two numbers be $x$ and $y$ .
$x^{2}$ $+$ $y^{2}$ $\to$ $156$
$x$ $\to$ 5
$x$ $\to$ $5 \times 5$ $\to$ $25$
Substituting, $25$ $+$ $y^{2}$ $\to$ $156$
$y^{2}$ $\to$ $156 - 25$ $\to$ $131$