The sum of the squares of the eccentricites of x2-4-y2-3-1 and x2-4-y2-3-1 is

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The sum of the squares of the eccentricites of $\frac{x^{2}}{4} + \frac{y^{2}}{3} = 1$ and $\frac{x^{2}}{4} - \frac{y^{2}}{3} = 1$ is

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\frac{x^{2}}{4} + \frac{y^{2}}{3} = 1

\frac{x^{2}}{4} - \frac{y^{2}}{3} = 1

\frac{x^{2}}{4} + \frac{y^{2}}{1} = 1

x^{2} + y^{2} = 3

x^{2} + y^{2} + \frac{1}{x^{2}} + \frac{1}{y^{2}} = 4

x^{2} + y^{2}

\frac{x^{2}}{4} + y^{2} = 1

\frac{x^{2}}{a^{2}} + y^{2} = 1

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