The sum of the squares of two consecutive odd positive integers is 394. Find them.

Open in App

Solution

Let the consecutive odd positive integers be 2x - 1 and 2x + 1. Then, $(2 x - 1)^{2} + (2 x + 1)^{2} = 394 \Rightarrow 8 x^{2} + 2 = 394 \Rightarrow 4 x^{2} = 392 \Rightarrow x = 6$
$∴$ the two odd consecutive odd positive integers are $11$ and $13$ .

Suggest Corrections

Similar questions

290

Find two consecutive positive odd integers sum of whose squares is 290?

290

Find two consecutive odd positive integers, sum of whose squares is 970.

Join BYJU'S Learning Program