The sum of the squares of two consecutive positive even numbers is 348. Represent this in equation form.

$n^{2} + (n - 2)^{2} = 348$

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$n^{2} + (n + 2)^{2} = 348$

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$n^{2} + (n + 3)^{2} = 348$

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$n^{2} + (n + 2)^{2} = 348 + n$

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Solution

The correct option is B
$n^{2} + (n + 2)^{2} = 348$

If "n" is an even number, it's consecutive positive even number will be n+2.

Given:The sum of the squares of two consecutive positive even numbers is 348.

So, $n^{2} + (n + 2)^{2} = 348$

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