Question

The sum of the squares of two numbers is $98$ and square of their difference is $56$. The product of the two numbers is

• A. $21$
• B. $24$
• C. $33$
• D. $19$

Answer 1

The correct option is A $21$

Let, the two numbers be $x,y$ such that $(x>y)$ respectively.

According to the question, $x^2+y^2=98$

and $(x-y{)}^2=56$

$⟹x^2+y^2-2xy=56$

$⟹98-2xy=56$

$⟹2xy=98-56=42$

$\therefore xy=21$

Hence, the product of the two numbers $=21$