wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The sum of the squares two consecutive positive integers is 365.Find the integers.

Open in App
Solution

let the no. be x and x+1
then we have x²+(x+1)²=365
2x²+2x-364=0
x²+x-182=0
x²+14x-13x-182=0
(x+14)(x-13)=0
That gives x=13 and x=-14, Avoiding as a negative value.
One number is 13 and other one 14


flag
Suggest Corrections
thumbs-up
243
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Solving QE by Factorisation
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon