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Question

The sum of the third and the ninth term of an AP is 10. Find a possible sum of the first 11 terms of this AP?

A
55
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B
44
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C
66
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D
None of these
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Solution

The correct option is A 55

T3 + T9 = 10

a+2d + a+ 8d = 10

2a+10d=10--------- (1)

Sum to 11 terms = 11/2 (2a+10d)

From 1, sum to 11 terms =11/2 (10) = 55


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