The sum of the three zeroes of the polynomial $p x^{3} + q x^{2} + r x + s$ is

\frac{- q}{s}

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\begin{matrix} s q \end{matrix}

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- \begin{matrix} q p \end{matrix}

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\begin{matrix} q s \end{matrix}

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Solution

The correct option is A $\frac{- q}{s}$
We have,
$p x^{3} + q x^{2} + r x + S$

let the zeroes be $α, β, γ$

we know that,
sum of zeroes = $\frac{- (c o e f f i c i e n t o f s e c o n d h i g h e s t p o w e r)}{c o e f f i c i e n t o f h i g h e s t p o w e r}$

Hence,
$α + β + γ = \frac{- q}{p}$

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α, β

γ

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y = p x^{3} + q x^{2} + r x + s

y = p x^{3} + q x^{2} + r x + s

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