Question

The sum of there consecutive odd numbers is $189.$ Find the numbers.

Answer 1

Let the first number be $x$

Then, the next odd number would be $x+2$

The last would be $x+4$

Then, the equation is

$x+(x+2)+(x+4)=189$

$\Rightarrow x+x+2+x+4=189$

$\Rightarrow 3x+6=189$

$\Rightarrow 3x=189-6$

$\Rightarrow 3x=183$

$\Rightarrow x=\frac{183}{3}$

$\Rightarrow x=61$

$\therefore$ first number$=x=61.$

second number $=x+2=61+2=63$

Third number $=x+4=61+4=65$

$\therefore$ so, the three numbers are $61,63$ and $65$