Question

The sum of three consecutive even integers is $168$, what are the integers?

Answer 1

What are the integers:

Let, the three consecutive even integers be $x$, $x+2$ and $x+4$.

Then, the sum will be,

$\begin{array}{rcl}x+\left(x+2\right)+\left(x+4\right)& =& 168\\ & \Rightarrow & 3x+6=168\\ & \Rightarrow & 3x=168-6\\ & \Rightarrow & 3x=162\\ & \Rightarrow & x=\frac{162}{3}\\ \therefore x& =& 54\end{array}$

Hence, the required three consecutive even integers are $\mathbf{54}$, $\mathbf{56}$ and $\mathbf{58}$.