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Question

The sum of three consecutive even integers is 66. Find all the three integers.


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Solution

Finding the numbers:

Let the three consecutive even integers be x-2,x,x+2.

Now, the sum of three consecutive even integers is 66.

x-2+x+x+2=663x=66x=663=22

x-2=22-2=20x=22x+2=22+2=24

Thus, 20,22,24 are three consecutive even integers whose sum is 66.


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