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Question
The Sum of three consecutive even numbers is 52 more than their average. What will be the first of these numbers?
The Sum of three consecutive even numbers is 52 more than their average. What will be the first of these numbers?
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Solution
The correct option is B 24
Let the three consecutive even numbers be n,n+2 and n+4.
Given, n+n+2+n+4 = 52+(3n+6)/3
3n+6 = 52 + n + 2
n =24
Let the three consecutive even numbers be n,n+2 and n+4.
Given, n+n+2+n+4 = 52+(3n+6)/3
3n+6 = 52 + n + 2
n =24
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