The sum of three consecutive integers is 48. Find the integers.

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Solution

Dear Student,

$L e t t h e m i d d l e i n t e g e r o f t h e t h r e e i n t e g e r s b e x . T h e n, i n t e g e r s u c c e e d i n g x = (x + 1) a n d i n t e g e r p r e c e e d i n g x = (x - 1) . N o w, a c c o r d i n g t o q u e s t i o n, (x - 1) + x + (x + 1) = 48 \Rightarrow x + x + x + 1 - 1 = 48 \Rightarrow 3 x = 48 \Rightarrow x = 12 . T h u s, i n t e g e r p r e c c e d i n g 12 i s 11 a n d s u c c e e d i n g i t i s 13 . H e n c e, t h e r e q u i r e d t h r e e i n t e g e r s a r e 11, 12 a n d 13 .$

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