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Question

The sum of three consecutive integers is equal to 192. What is the product of these numbers?

A
216000
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B
7077888
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C
576
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D
110592
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E
262080
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Solution

The correct option is E 262080
To get the three consecutive numbers whose sum is 192, we get the equation as,
x+(x+1)+(x+2)=192
3x+3=192
3x=1923 =189
x=1893
x=63
So the first number out of the three consecutive numbers is 63,
The three numbers are 63,64 and 65.
The product of these numbers is,
63×64×65=262080
Hence the correct answer is option E, the number 262080
Ans: E

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