Question

The sum of three consecutive multiples of $11$ is $363$. find multiples.

Answer 1

Let the first multiple be x.

$2^{nd}$ multiple x + 11

$3^{rd}$ multiple x + 22

$x+(x+11)+(x+22)=363$

$\therefore 3x+33=363$

$\therefore 3x=363-33$

$\therefore 3x=330$

$x=110$