Question

The sum of three consecutive multiples of $11$ is $363$. Find these multiples.

• A. $110,121,132$
• B. $99,77,187$
• C. $110,99,154$
• D. none

Answer 1

Answer: (A)

$110,121,132$

Let the three consecutive multiples of $11$ are $11x,$ $11x+11$ and $11x+22$

Their sum is $363$

$11x+11x+11+11x+22=363$

$33x+33=363$

$33x=363-33$

$33x=330$

$x=\frac{330}{33}$

$x=10$

First multiple $=11x=11\times 10=110$

Second multiple $=11x+11=110+11=121$

Third multiple $=11x+22=110+22=132$