Question

The sum of Three consecutive multiples of $7$ is $63$. Find these multiples.

Answer 1

Lets observe the $7th$ table.

$7,14,21,28,....$

$\Rightarrow$ $7,7+7,7+14,.....$

i.e., Every consecutive multiple of $7$, is increased by $7$ from its previous multiple.

Let the first multiple of $7$ be $x$.

$\Rightarrow$ The first three consecutive multiples of $7$are $x,x+7$ and $x+14$.

It is given that, sum of Three consecutive multiples of $7$ is $63$.

$\Rightarrow x+x+7+x+14=63$

$\Rightarrow 3x+21=63$

$\Rightarrow 3x=63-21$

$\Rightarrow 3x=42$

$\Rightarrow x=\frac{42}{3}$

$\Rightarrow x=14$

So, $x=14$

$x+7=14+7=21$

$x+14=14+14=28$

Therefore, the required numbers are $14,21$ and $28$.