Question

The sum of three consecutive multiples of $9$ is $135$, then the multiples are

• A. $36,45,54$
• B. $45,54,63$
• C. $27,36,45$
• D. None of the above.

Answer 1

The correct option is A $36,45,54$

If $p$ is a multiple of $9$, then next two multiples are $p+9$ and $p+18$
According to the question:
$⟹p+(p+9)+(p+18)=135$
$⟹3p+27=135$
$⟹3p=135-27$
$⟹3p=108$
$⟹p=36$
Thus,

$p=36$

$p+9=45$

$p+18=54$

Hence the required multiples are $36,45,54$